Canterbury Rapid Championship 2022: Pairing of round 4

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  1 = Dib,Michel           ( 2.0) - Flatow,A (Fred)      ( 3.0) =  10 -   7 = 0 - 1
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  2 = Merhi,Alexandre      ( 2.0) - Shaw,Ralph           ( 0.0) =   8 -   6 = 1 - 0
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  3 = Meireles,Carlos Xavi ( 0.0) - Chiara,Vincenzo      ( 1.0) =   9 -   5 = 1 - 0
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  4 = Dragalchuk,Vladislav ( 3.0) - Allison,Graham       ( 1.0) =   1 -   4 = 1 - 0
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  5 = Marino,Retano        ( 1.0) - Ullah,Sami           ( 2.0) =   2 -   3 = 0 - 1
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